correctly show source names
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b327d91976
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e10432dae4
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@ -1506,7 +1506,9 @@ function createDashboard() {
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frame.innerHTML = '';
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frame.innerHTML = '';
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}
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}
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function sourceName(v){
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function sourceName(v){
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if (v == 0) return "N2K";
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for (let n in channelList){
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for (let n in channelList){
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if (v == channelList[n].id) return n;
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if (v >= channelList[n].id && v <= channelList[n].max){
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if (v >= channelList[n].id && v <= channelList[n].max){
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return n;
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return n;
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}
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}
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